J's answer to serendipity's Secondary 4 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Recall the property :
tan(A + B) = (tan A + tan B) / (1 - tan A tan B)
So, (tan 45° + tan 15°) / (1 - tan 45° tan 15°)
(A here = 45° and B = 15°)
= tan(45° + 15°)
= tan 60°
= √3 (recall your special angles)
tan(A + B) = (tan A + tan B) / (1 - tan A tan B)
So, (tan 45° + tan 15°) / (1 - tan 45° tan 15°)
(A here = 45° and B = 15°)
= tan(45° + 15°)
= tan 60°
= √3 (recall your special angles)
Date Posted:
3 years ago
360 Tutoring Program