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secondary 4 | A Maths
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pls help thanks
Date Posted: 2 years ago
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Recall the property :
tan(A + B) = (tan A + tan B) / (1 - tan A tan B)
So, (tan 45° + tan 15°) / (1 - tan 45° tan 15°)
(A here = 45° and B = 15°)
= tan(45° + 15°)
= tan 60°
= √3 (recall your special angles)
tan(A + B) = (tan A + tan B) / (1 - tan A tan B)
So, (tan 45° + tan 15°) / (1 - tan 45° tan 15°)
(A here = 45° and B = 15°)
= tan(45° + 15°)
= tan 60°
= √3 (recall your special angles)
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