J's answer to Alex Tan's Secondary 4 E Maths Singapore question.
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Given : 4/x + 3/(x + 1) = 2
If x = -1, then x + 1 = 0.
This means that 3/(x + 1) = 3/0, which is undefined since division by 0 is undefined. So the left hand side of the equation is undefined and cannot equal 2 on the right hand side.
So, x = -1 is not admissible.
If x = -1, then x + 1 = 0.
This means that 3/(x + 1) = 3/0, which is undefined since division by 0 is undefined. So the left hand side of the equation is undefined and cannot equal 2 on the right hand side.
So, x = -1 is not admissible.
Date Posted:
3 years ago