AC Lim's answer to xuannie's Primary 6 Maths Fractions Singapore question.
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Answer =75
At 1st
A=10u
B= 10u+75
In the end, all same
All have 12u as C gave A 20% = 1/5
C left 4/5,
Hence, A =9u +1/5
Compare to C, 9u= 3/5,
Therefore, 1/5 = 3u.
When B receive 1u (1/10) from A
B have 11u + 25
In the end, B have ¾ of 11u+25
= (33u+75)/4
Therefore,
(33u+75)/4 = 12u
33u+75=48u
75=15u
1u=5
B at 1st = (10×5 )+25 = 75.
At 1st
A=10u
B= 10u+75
In the end, all same
All have 12u as C gave A 20% = 1/5
C left 4/5,
Hence, A =9u +1/5
Compare to C, 9u= 3/5,
Therefore, 1/5 = 3u.
When B receive 1u (1/10) from A
B have 11u + 25
In the end, B have ¾ of 11u+25
= (33u+75)/4
Therefore,
(33u+75)/4 = 12u
33u+75=48u
75=15u
1u=5
B at 1st = (10×5 )+25 = 75.
Date Posted:
3 years ago
Take note
At 1st
B= 10u +25
At 1st
B= 10u +25
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