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Question
primary 6 | Maths
| Fractions
4 Answers Below
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Date Posted: 3 years ago
Views: 598
question source?
It was from a worksheet assigned by my teacher
Answer =75
At 1st
A=10u
B= 10u+25
In the end, all same
All have 12u as C gave A 20% = 1/5
C left 4/5,
Hence, A =9u +1/5
Compare to C, 9u= 3/5,
Therefore, 1/5 = 3u.
When B receive 1u (1/10) from A
B have 11u + 25
In the end, B have ¾ of 11u+25
= (33u+75)/4
Therefore,
(33u+75)/4 = 12u
33u+75=48u
75=15u
1u=5
B at 1st = (10×5 )+25 = 75.
At 1st
A=10u
B= 10u+25
In the end, all same
All have 12u as C gave A 20% = 1/5
C left 4/5,
Hence, A =9u +1/5
Compare to C, 9u= 3/5,
Therefore, 1/5 = 3u.
When B receive 1u (1/10) from A
B have 11u + 25
In the end, B have ¾ of 11u+25
= (33u+75)/4
Therefore,
(33u+75)/4 = 12u
33u+75=48u
75=15u
1u=5
B at 1st = (10×5 )+25 = 75.
See 4 Answers
Answer =75
At 1st
A=10u
B= 10u+75
In the end, all same
All have 12u as C gave A 20% = 1/5
C left 4/5,
Hence, A =9u +1/5
Compare to C, 9u= 3/5,
Therefore, 1/5 = 3u.
When B receive 1u (1/10) from A
B have 11u + 25
In the end, B have ¾ of 11u+25
= (33u+75)/4
Therefore,
(33u+75)/4 = 12u
33u+75=48u
75=15u
1u=5
B at 1st = (10×5 )+25 = 75.
At 1st
A=10u
B= 10u+75
In the end, all same
All have 12u as C gave A 20% = 1/5
C left 4/5,
Hence, A =9u +1/5
Compare to C, 9u= 3/5,
Therefore, 1/5 = 3u.
When B receive 1u (1/10) from A
B have 11u + 25
In the end, B have ¾ of 11u+25
= (33u+75)/4
Therefore,
(33u+75)/4 = 12u
33u+75=48u
75=15u
1u=5
B at 1st = (10×5 )+25 = 75.
Take note
At 1st
B= 10u +25
At 1st
B= 10u +25
done
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The number of units for each person is worked out by going through each change from the end when everyone had equal number of beads.
The last column shows the number of units each person had at first.
The last column shows the number of units each person had at first.
Date Posted:
3 years ago
done
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Backwards
total unchanged - internal transfer
total unchanged - internal transfer
Date Posted:
3 years ago
done
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Hope this helps✨
Date Posted:
3 years ago
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