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junior college 1 | H1 Maths
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huihuibuhui
Huihuibuhui

junior college 1 chevron_right H1 Maths chevron_right Singapore

Hi, my senior needs help with this question part (ii) (a.). Thank you :)

Date Posted: 3 years ago
Views: 552
J
J
3 years ago
ii a)

①Repetitions allowed
② digit 5 exactly once
③ letter H exactly twice

First 3 characters are digits. Last 3 characters are letters.


So we can have :

①5 _ _ H H _
②5 _ _ H _ H
③5 _ _ _ H H

④_ 5 _ H H _
⑤_ 5 _ H _ H
⑥_ 5 _ _ H H

⑦_ _ 5 H H _
⑧_ _ 5 H _ H
⑨_ _ 5 _ H H


This is basically saying :

Number of ways to arrange the 5 and H
= 3C1 x 3C2
= 3 x 3
= 9


So for the blanks, we cannot pick 5 or H already.

For numbers we can only choose from 12346 (total 5 choices)
For letters we can only choose from ABCDEFG (total 7 choices)


For each of the 9 arrangements above,

Number of ways to pick first blank digit
= 5

Number of ways to pick second blank digit
= 5

Number of ways to pick the blank letter
= 7

Total number of ways = 9 x 5 x 5 x 7 = 2565
J
J
3 years ago
Now, if there is no restriction and repetitions are allowed,

Number of ways = 6 x 6 x 6 x 8 x 8 x 8
= 110592


Required probability = 2565/110592
= 95/4096
J
J
3 years ago
Edit :


9 x 5 x 5 x 7 = 1575 instead of 2565

(Keyed in 9 x 5 x 57 by mistake in calculator)


Required probability = 1575/110592

= 175/12288
huihuibuhui
Huihuibuhui
3 years ago
Thank you so much :)

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Kahwai
Kahwai's answer
232 answers (A Helpful Person)
1st
Not that difficult
Need to analyze a bit

These are the answers

Use box method Orelse exam don’t know how to do
huihuibuhui
Huihuibuhui
3 years ago
Thabk you so much :)
J
J
3 years ago
The total for part aii) should be 6³ x 8³ instead of 6³ x 7³ since there are 8 possible choices from A to H and not 7.

Likewise, for i), it would be 8C1 x 7C1 x 6C1 for the letters instead of 7C1 x 6C1 x 5C1