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secondary 2 | Maths
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Hi can help me with part ii of the question. I used 2/3(4x22/7x7x7) but I can’t get the answer. Thks
Date Posted: 3 years ago
Views: 353
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Total area = 2/3[4(22/7)(7^2)] + [(22/7)(7^2)] =564.6666667 ≈ 564.67 (2dp)
You need to add the shaded area also... which is just pi(r^2) because you can see it’s 2 semicircle.
Oh I see...Thks!
Sorry i don’t understand the working. Thought the surface area would : area of cross section of the solid machine X 2 (ie 37.9 x 2) + area of smalk n large rectangle ( 5x28x2+2x28x2) + the hollow semi circle which i don’t know how to find
What do you mean ? >_> small and large rectangle ?
Oh sorry I think I have replied to the wrong question. Thks
Hahaha Okayy !
Would you able to help me with the question I post in the morning on the cross section of trapezium and semicircle?. Thks
done
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Hope it helps:)
Date Posted:
3 years ago
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