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Question
secondary 3 | A Maths
2 Answers Below
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pn 6
Date Posted: 3 years ago
Views: 232
Gradient of OA
= (5 - 0) / (1 - 0)
= 5
For OB to be perpendicular to OA, the product of their gradients must be -1.
So,
gradient of OB x 5 = -1
gradient of OB = -1/5
But gradient of OB
= (q - 0) / (p - 0)
= q/p
This means that q/p = -1, so that q = -p.
We can just pick any combination of numbers except for p = 0.
= (5 - 0) / (1 - 0)
= 5
For OB to be perpendicular to OA, the product of their gradients must be -1.
So,
gradient of OB x 5 = -1
gradient of OB = -1/5
But gradient of OB
= (q - 0) / (p - 0)
= q/p
This means that q/p = -1, so that q = -p.
We can just pick any combination of numbers except for p = 0.
See 2 Answers
done
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y = -5x
Date Posted:
3 years ago
done
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for your reference...
Date Posted:
3 years ago
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