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primary 6 | Maths | Measurement
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june  tan
june tan

primary 6 chevron_right Maths chevron_right Measurement chevron_right Singapore

Pls help ASAP. Thanks

Date Posted: 3 years ago
Views: 220
AC Lim
AC Lim
3 years ago
In the end, all same number of marbles.
132 ÷ 3 = 44

Cindy give 27 to Ali
Cindy have 71 after received half from Benny

Ali have 44 -27 = 17 after give to Benny.
Benny left 44 after gave half to Cindy,
SO, Benny have 44 x 2 =88 after received from Ali

At 1st, Benny have u
Received 2u + 19 from Ali.
Total Benny have now = 88
u + 2u + 19 = 88
3u = 69
1u = 23.

Ali at 1st = 17 + (2u+19)
= 17 + (2x23 + 19)
= 17 + 65
= 82
Hope this helps
june  tan
june tan
3 years ago
Thx

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AC Lim
Ac Lim's answer
12340 answers (A Helpful Person)
Hope this helps
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Han Khng
Han Khng's answer
4 answers (A Helpful Person)
1st
Imagine you’re travelling back in time...

Tracing your steps, you will reverse each transaction to know what they have at first. Your first clue is that they end up having the same number. Therefore,

132/3 = 44 marbles each in the end.

Referring to the image, from top to bottom, you will see how each transactions is reversed.

Note that Ali was involved in FIRST and LAST transaction only. After his 1st transaction, he had 17 left. How do we know? Because after the last transaction, he has the same number as everyone else. So, when reversing the very 1st transaction, we must remember to account for his marbles on hand.

Now, how do we check?

The circled items are the initial number BEFORE any transaction takes place, therefore your ANSWERS. Check that your answers are right by adding all these numbers together to make sure they total to 132.

Hope this helps.