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secondary 3 | E Maths
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hi, I need help for this qn as I do not really understand this topic, thank you!
Date Posted: 3 years ago
Views: 159
The graph in part a is typical of a power -1 graph. Normally a graph of 1/x will have the horizontal "untouchable" line at y = 0. In this case, the "untouchable" line is at y = 1. So, there is an additional "+1" at the end of the equation.
y = 1/x + 1
So, b = 1, n = -1 (actually, a can be any negative odd integer)
The graph in part b is typical of a power 3 graph. The factor to add here is a +"1".
So, b = 1, n = 3.
For the third one, I skip the steps, b = -2, n = 2.
y = 1/x + 1
So, b = 1, n = -1 (actually, a can be any negative odd integer)
The graph in part b is typical of a power 3 graph. The factor to add here is a +"1".
So, b = 1, n = 3.
For the third one, I skip the steps, b = -2, n = 2.
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Hope this helps (:
Date Posted:
3 years ago
O Level students only learn powers -2, -1, 0, 1, 2 and 3.
They do not learn power -3, so for part a, n = -1 is more appropriate.
They do not learn power -3, so for part a, n = -1 is more appropriate.
Anyway you will need to explain the term "asymptote" to the student, as the vast majority of E Maths students do not learn the term "asymptote".
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