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primary 6 | Maths
| Fractions
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Date Posted: 4 years ago
Views: 450
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Hope this helps
Date Posted:
4 years ago
Thank you
This is an incorrect approach. The question did not specify if the units for R and for T are the same but you have assumed it
Secondly, the area of S is 8/9 the area of R+T, not 8 times.
Edit : a third error was, the question was not asking for shaded area as a fraction of the unshaded fraction area.
Secondly, the area of S is 8/9 the area of R+T, not 8 times.
Edit : a third error was, the question was not asking for shaded area as a fraction of the unshaded fraction area.
Oh oops, J's right. I missed out that one. How about you show a working so Super knows what went wrong?
ratio of S to R+T = 8 : 9
¼ of S is shaded, so number of units of S that is shaded
= 8 ÷ 4 = 2
(Or 8 x ¼ = 2)
Area of whole figure
= Area of S + Area of R + Area of T - Area of overlap(shaded area)
= 8 units + 9 units - 2 units
= 15 units
Fraction of figure that is shaded
= 2/15
¼ of S is shaded, so number of units of S that is shaded
= 8 ÷ 4 = 2
(Or 8 x ¼ = 2)
Area of whole figure
= Area of S + Area of R + Area of T - Area of overlap(shaded area)
= 8 units + 9 units - 2 units
= 15 units
Fraction of figure that is shaded
= 2/15
Thanks for the help Arennea and J.
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