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Alternative working for :
Case 2
Number of ways to choose 2 people from 5 to give the gifts = 5C2
Number of ways to choose who gets 1 gift and who gets 2 gifts among the pair
= 2!
5C2 x 2! = 10 x 2 = 20
Case 3
Number of ways to choose 3 people from 5 to give each 1 gift = 5C3 = 10
Case 2
Number of ways to choose 2 people from 5 to give the gifts = 5C2
Number of ways to choose who gets 1 gift and who gets 2 gifts among the pair
= 2!
5C2 x 2! = 10 x 2 = 20
Case 3
Number of ways to choose 3 people from 5 to give each 1 gift = 5C3 = 10
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