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Secondary 1 | Maths
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Pls help...
3x² - 2x - 6 = 0 (either multiply by -1 on both sides of equation or bring over each term to the right)
x² - ⅔x - 2 = 0 (divide by 3)
x² - 2(⅓)x + (⅓)² - (⅓)² - 2 = 0
The first 3 terms are now in the form
a² - 2(a)(b) + b² and can be rewritten as (a - b)²
(x - ⅓)² - 1/9 - 2 = 0
(x - ⅓)² = 2 + 1/9 = 19/9
x - ⅓ = √(19/9) or x - ⅓ = -√(19/9)
x = ⅓ + √(19/9) + ⅓ or x = ⅓ - √(19/9)
x ≈ 1.79 or x ≈ -1.12
(2d.p)
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