Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | E Maths
One Answer Below
This question need another answer.
How to do question 3. Both part (a) and (b). Pls provide a step by step workings and solutions
Date Posted: 4 years ago
Views: 493
See 1 Answer
(a) 150g of Molybdenum is 3% of the maximum weight.
Thus the maximum weight = 100/3 * 150g = 5000g.
The answer is 5kg.
(b) For 5kg of the stainless steel, 0.030% is Sulphur.
Thus the weight of Sulphur needed = 0.030/100 * 5000g = 1.5g.
The answer is 1.5g.
Hope this helps!
Thus the maximum weight = 100/3 * 150g = 5000g.
The answer is 5kg.
(b) For 5kg of the stainless steel, 0.030% is Sulphur.
Thus the weight of Sulphur needed = 0.030/100 * 5000g = 1.5g.
The answer is 1.5g.
Hope this helps!
360 Tutoring Program