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Write down 3 cases for the situation -> case 1 is no oldest man or women. Case 2 is one oldest man, no oldest women. Case 3 is oldest women but no oldest man.
7 men with one oldest, means there are 6 non-oldest. 6 women with one oldest means there are 5 non-oldest women.
7 men with one oldest, means there are 6 non-oldest. 6 women with one oldest means there are 5 non-oldest women.
Date Posted:
4 years ago
Thanks alot! Appreciate the help
No prob. Didn't know H3 math has this topic. I thought it's under the usual H2 math topic, called permutations and combinations. But they learn this on yr 2 though, under statistics.
I learn this in poly haha
But when i wanted to ask the question there wasn't a option to choose the level of education for permutations and combinations so i just went with a random one
But when i wanted to ask the question there wasn't a option to choose the level of education for permutations and combinations so i just went with a random one
Ah I see. Damn categories lol.. See u around.