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secondary 4 | A Maths
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Hi good evening! How do i solve this? I have no idea how to show part i :/
Date Posted: 4 years ago
Views: 233
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Good evening Candice!
The line x = 3 is contained in the first and fourth quadrants while the line y = -4 is contained in the third and fourth quadrants.
Since the centre of the circle is in the second quadrant, the circle must be at the top left “quadrant” of the intersection of lines x = 3 and y = -4.
The diagram is as I have presented.
Let me know if you need more explanation and I will explain them again!
Hang on for the subsequent parts.
The line x = 3 is contained in the first and fourth quadrants while the line y = -4 is contained in the third and fourth quadrants.
Since the centre of the circle is in the second quadrant, the circle must be at the top left “quadrant” of the intersection of lines x = 3 and y = -4.
The diagram is as I have presented.
Let me know if you need more explanation and I will explain them again!
Hang on for the subsequent parts.
Date Posted:
4 years ago
Thank you! I understand now :D
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Part two by forming three simultaneous equations in three unknowns
Date Posted:
4 years ago
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Parts three and four
Let me know if you need more explanations for any of the parts and I will explain them again.
Let me know if you need more explanations for any of the parts and I will explain them again.
Date Posted:
4 years ago
Its fine now thanks :)
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