Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
junior college 1 | H2 Maths
5 Answers Below
Anyone can contribute an answer, even non-tutors.
Please help thank you!
Date Posted: 4 years ago
Views: 520
See 5 Answers
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Correct is this expression which equates to 7.219187054.
I am currently troubleshooting my previous answer, but if I am unable to find out the exact error in 15 minutes, I will continue at night.
The shape of the volume of rotation is something like a conical flask.
I am currently troubleshooting my previous answer, but if I am unable to find out the exact error in 15 minutes, I will continue at night.
The shape of the volume of rotation is something like a conical flask.
Date Posted:
4 years ago
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Corrected
Date Posted:
4 years ago
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Here is the relevant sketch of the graph using Desmos. In that interval, the coordinates of the intercepts are (-pi/2, 0) for the x-intercept and (0, 1) for the y-intercept. The vertical blue and green lines are the boundary conditions for the curve.
Date Posted:
4 years ago
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Second part
Date Posted:
4 years ago
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Third part. Not so sure about this one.
The squaring of the f(x) in this integral negates the need to split the integral into the regions -2 to -pi/2 and -pi/2 to 1.
The squaring of the f(x) in this integral negates the need to split the integral into the regions -2 to -pi/2 and -pi/2 to 1.
Date Posted:
4 years ago
Hang on. Something is not right with my answer. Correct is 7.219.
Never mind, how stupid of me. The limits are 1 and -2, not 2 and -1. Rewriting my workings soon.
Edit: Corrected two posts later.
Edit: Corrected two posts later.
360 Tutoring Program