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Question
primary 6 | Maths
| Fractions
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I got my and as 91 but it is wrong
Date Posted: 5 years ago
Views: 340
unit cost
p: 1 u
c: 3 u
cost
p: 31 u
c: 45 u
total = 76 u
1/4 = 76 u
remaining money = 3/4
3/4 of remaining = 9/16
so
9/16 = 76 u x 3 x 3/4 = 171 u
total no. of calculators bought
= 15 + 171/3 = 72
...
p: 1 u
c: 3 u
cost
p: 31 u
c: 45 u
total = 76 u
1/4 = 76 u
remaining money = 3/4
3/4 of remaining = 9/16
so
9/16 = 76 u x 3 x 3/4 = 171 u
total no. of calculators bought
= 15 + 171/3 = 72
...
My answer is 72.
See 3 Answers
done
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Hope this helps :)
Date Posted:
5 years ago
Are you sure that 91 is wrong?
The question mentioned that he bought more calculators with ¾ of his remaining money, which equals ¾ of ¾ of his total money at first.
¾ x ¾ = 9/16 , so in your last equation you should be finding 9/16 x instead of ¾ x
¾ x ¾ = 9/16 , so in your last equation you should be finding 9/16 x instead of ¾ x
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We have to use the fraction of a fraction method to solve the question.Hope my solution will help you to understand the question better.
Date Posted:
5 years ago
Slight error in your working, it should be 304 ÷ 16 = 19, not 304 ÷ 9 = 19
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Date Posted:
5 years ago
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