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secondary 3 | E Maths
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How to do 4ii)
Date Posted: 4 years ago
Views: 169
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Tan PQS = 3/4
Angle PQS = inverse Tan (3/4)
Use calculator to find tan^-1(3/4)
=36.87
h = 5 (Pythagoras theorem)
Angle PQS = angle QSR (alt angle)
Tan QSR = QR / 5
QR = 3/4 x 5
= 3.75
Angle PQS = inverse Tan (3/4)
Use calculator to find tan^-1(3/4)
=36.87
h = 5 (Pythagoras theorem)
Angle PQS = angle QSR (alt angle)
Tan QSR = QR / 5
QR = 3/4 x 5
= 3.75
Since angle PQS = angle QSR,
Tangent QSR = Tangent PQS = 3/4
The h in solution is QS = 5
Tangent QSR = Tangent PQS = 3/4
The h in solution is QS = 5
It was great
Another method is to use similar triangles.
Since angle PQS = angle QSR and angle QPS = angle RQS, triangle PQS is similar to QSR.
QS = 5 (from Pythagoras)
QR / PS = QS / QP
QR = 3 x 5 / 4
= 3.75
Since angle PQS = angle QSR and angle QPS = angle RQS, triangle PQS is similar to QSR.
QS = 5 (from Pythagoras)
QR / PS = QS / QP
QR = 3 x 5 / 4
= 3.75
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