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secondary 3 | E Maths
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Henry Kor
Henry Kor

secondary 3 chevron_right E Maths chevron_right Singapore

Hi could someone please help me with part IV? Thanks!

Date Posted: 5 years ago
Views: 522
snell
Snell
5 years ago
(iv)
C(2, 1)

method
1. draw y = x + 1 in graph grid
it passes thru' A(-1, 0), (0, 1) & (1, 2)

2. since it is line of symmetry,
equal dist. of B(0, 3) from (1, 2) would give equal dist. from (1, 2) to C, which is (2, 1)

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Muhammed Anas
Muhammed Anas's answer
15 answers (Tutor Details)
1st
Whenever you're given such a question, first mark out the x and y-intercepts (and any other convenient points) of the new line. By substituting x=0 and y=0 we know that the line passes through A(-1,0) and (0,1). Since this is the line of symmetry of the triangle, it implies that it is the perpendicular bisector of the line segment BC. This means that points B and C are equidistant from the line. By observation, we see that B is 1 "big square" away from the line. C must therefore be the "mirror reflection" of B about the line.