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secondary 3 | E Maths
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Hi could someone please help me with part IV? Thanks!
Date Posted: 4 years ago
Views: 464
(iv)
C(2, 1)
method
1. draw y = x + 1 in graph grid
it passes thru' A(-1, 0), (0, 1) & (1, 2)
2. since it is line of symmetry,
equal dist. of B(0, 3) from (1, 2) would give equal dist. from (1, 2) to C, which is (2, 1)
C(2, 1)
method
1. draw y = x + 1 in graph grid
it passes thru' A(-1, 0), (0, 1) & (1, 2)
2. since it is line of symmetry,
equal dist. of B(0, 3) from (1, 2) would give equal dist. from (1, 2) to C, which is (2, 1)
See 1 Answer
done
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Whenever you're given such a question, first mark out the x and y-intercepts (and any other convenient points) of the new line. By substituting x=0 and y=0 we know that the line passes through A(-1,0) and (0,1). Since this is the line of symmetry of the triangle, it implies that it is the perpendicular bisector of the line segment BC. This means that points B and C are equidistant from the line. By observation, we see that B is 1 "big square" away from the line. C must therefore be the "mirror reflection" of B about the line.
Date Posted:
4 years ago
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