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secondary 4 | E Maths
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Date Posted: 5 years ago
Views: 276
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done
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clear
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My personal strategy for such equations is to clear the equations of all fractions first.
Date Posted:
5 years ago
In your expression, for the first fraction, the '5' goes into the denominator
This becomes 3(3y + 12) divided by (5y).
For the second fraction, the '(2y)' is divided by the entire chunk, so the '5' goes into the numerator to become
10y divided by (3y + 12)
This becomes 3(3y + 12) divided by (5y).
For the second fraction, the '(2y)' is divided by the entire chunk, so the '5' goes into the numerator to become
10y divided by (3y + 12)
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