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secondary 3 | E Maths
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need help with question 7
Date Posted: 7 years ago
Views: 399
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Didn't answer (a) since I saw that you had the answer there.
For (c), you use triangle BCD to figure out tan (ABC) = opposite/adj = 3/(11+2) = 3/13
(d) Given ABCD is a parallelogram, it means D must be on the same level as C (hence, y coordinate of D = 3) and that the distance between AB should be the same as CD (i.e. 2 units).
Therefore, D( -1+2, 3) = D(1,3)
OR
D (-1-2, 3) = D (-3,3)
They didn't state if D is in which side of the axis, so technically there's two possible points (you might want to draw out the two parallelograms if you don't understand).
For (c), you use triangle BCD to figure out tan (ABC) = opposite/adj = 3/(11+2) = 3/13
(d) Given ABCD is a parallelogram, it means D must be on the same level as C (hence, y coordinate of D = 3) and that the distance between AB should be the same as CD (i.e. 2 units).
Therefore, D( -1+2, 3) = D(1,3)
OR
D (-1-2, 3) = D (-3,3)
They didn't state if D is in which side of the axis, so technically there's two possible points (you might want to draw out the two parallelograms if you don't understand).
Date Posted:
7 years ago
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