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I see......but how to use v-t graph to solve this question?

I ve added an answer using v-t graph..

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Reasoning using v-t graph

Date Posted:
1 year ago

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Firstly, time does not have a direction. So '-2seconds' is wrong. Time must be a positive real number

Secondly the trajectory of the ball in the diagram is wrong, it is 'thrown upwards from distance 10m from ground' so the movement would be in my diagram as drawn.

To solve such questions you would need to solve a first path (upwards to an instantaneous stop) then a second path (downwards towards the ground). Total time taken will be 2s.

Secondly the trajectory of the ball in the diagram is wrong, it is 'thrown upwards from distance 10m from ground' so the movement would be in my diagram as drawn.

To solve such questions you would need to solve a first path (upwards to an instantaneous stop) then a second path (downwards towards the ground). Total time taken will be 2s.

Date Posted:
1 year ago

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Oh or alternatively you can pluck into this simple eqn and use the correct signs by designation a direction as positive

Date Posted:
1 year ago

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Can I solve this question by using this method? Firstly, calculate the time taken to reach max height.Secondly, calculate the time taken to reach the floor.Then adding to answer together.If my concept is wrong please tell me.Thank u very much.

Date Posted:
1 year ago