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Every orbital will be singly occupied with one electrons before any one orbital is doubly occupied. Therefore 3p4 will have 2 unpaired electrons as the 1st and 4th electrons pair up, leaving 2nd and 3rd unpaired.
4p2 will also have 2 unpaired as the 1st and 2nd electrons will singly occupy an orbital each.
4p2 will also have 2 unpaired as the 1st and 2nd electrons will singly occupy an orbital each.
Date Posted:
5 years ago
Thanks a lot for helping me...
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Hope this helps. You take the product of the probability and number of permutations to find the overall probability, then the relative abundace ratio.
Date Posted:
5 years ago
Thanks a lot....but I still didn't get why u use QR and RR ....