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Question
International Baccalaureatte | Further Maths HL
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Help me with 9 a
Date Posted: 5 years ago
Views: 496
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Could you pls show me in detail how to get (n-3)/4 *3. And the 1.75(1-p) ?I'm blur
Go see my 2nd post
See i saw dy...but dont really understood.Could u pls show te basic formula of that n!....
For nC4,why we didnt cutt tat (n-3)?How to know which one to cutt
Ok go look at the new post with colors. I divide both sides by nC3. I cancel out common factors.
Oktq
done
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clear
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Suppose the (1-p)must be at LHS right?Since (1-p)^n-4 / (1-p)^n-3= we cut that 3 off right?
Date Posted:
5 years ago
Use laws of indices...
n-4 - (n-3) = -1
So you'll get (1-p)^-1 instead
n-4 - (n-3) = -1
So you'll get (1-p)^-1 instead
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