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Question
primary 5 | Maths
| Area & Volume
2 Answers Below
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Pls help. Thanks!
Date Posted: 1 day ago
Views: 27
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Date Posted:
1 day ago
Not quite sure why C + D = E + F
But I got C + D by assuming height of C is U.
C+D = (1/2 x 12 x u) + (1/2 x 12 x (8-u))
C+D = 6u + 48 - 6u
C+D = 48
Shaded Area = Rectangle - A - B - C - D = 120 - 48 - 12 - 12 = 48
But I got C + D by assuming height of C is U.
C+D = (1/2 x 12 x u) + (1/2 x 12 x (8-u))
C+D = 6u + 48 - 6u
C+D = 48
Shaded Area = Rectangle - A - B - C - D = 120 - 48 - 12 - 12 = 48
@wil
C+D = E+F is derive from what you've done by assume height of C=u.
Since primary school may not learn solution for 6(8-u). I have upload another method to prove C+D = E+F.
C+D = E+F is derive from what you've done by assume height of C=u.
Since primary school may not learn solution for 6(8-u). I have upload another method to prove C+D = E+F.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hope this helps.
Date Posted:
1 day ago
Now, I understand. Thank you!
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