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junior college 2 | H2 Maths
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hi, possible to help with part 2 and 3?
Date Posted: 1 year ago
Views: 168
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As a solution, the answer is correct but it is missing quite a fair bit of explanation.
First, |1 - λ| = 1 - λ as 0 < λ < 1 => 0 < 1 - λ < 1.
The step of q x q = 0 vector should be there as well.
Lastly, there is a need to say that |p| = 1 as p is a unit vector. Other than that, everything is fine.
First, |1 - λ| = 1 - λ as 0 < λ < 1 => 0 < 1 - λ < 1.
The step of q x q = 0 vector should be there as well.
Lastly, there is a need to say that |p| = 1 as p is a unit vector. Other than that, everything is fine.
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