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secondary 3 | E Maths
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Date Posted: 2 years ago
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.
FD = sq root 2
Area of quarter circle AFD = Pi(x**)/2
Shaded area = quarter circle - triangle
= (1/2 Pi - 1) x**
Total area = rectangle + semi-circle
= (2 + 1/2 Pi)x**
Hence,
Fraction of shaded area
= ((1/2 Pi - 1)x**) / ((2 + 1/2 Pi)x**)
= (Pi - 2) / (Pi + 4)
Area of quarter circle AFD = Pi(x**)/2
Shaded area = quarter circle - triangle
= (1/2 Pi - 1) x**
Total area = rectangle + semi-circle
= (2 + 1/2 Pi)x**
Hence,
Fraction of shaded area
= ((1/2 Pi - 1)x**) / ((2 + 1/2 Pi)x**)
= (Pi - 2) / (Pi + 4)
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