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secondary 3 | E Maths
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Pls help with (b). Thank you
Date Posted: 2 years ago
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Total number of pieces is a product of number of pieces along the length and number of pieces along the breadth.
Look at it like this...
a 2 by 2 puzzle has 4 pieces in total.
Similarly, a 4 by 5 puzzle has 20 pieces in total.
By the same logic, a (x) by (y) puzzle has (x)(y)=xy pieces in total.
Therefore, a (n+5q) by (no. of pieces along length) puzzle has a total number of (2m+6p)(4n+20q) pieces.
Putting this information into equation form, we get:
(n+5q)(no. of pieces along length)=(2m+6p)(4n+20q).
By Factorising fully the term on the right side, we get:
(n+5q)(no. of pieces along length)=8(m+3p)(n+5q).
Hence, no. of pieces along length=8(m+3p)(n+5q)/(n+5q)=8(m+3p)
Hope this helps!!! You can ask me questions personally on telegram, just add my me @yuanqiiin. I will be happy to help you!
Look at it like this...
a 2 by 2 puzzle has 4 pieces in total.
Similarly, a 4 by 5 puzzle has 20 pieces in total.
By the same logic, a (x) by (y) puzzle has (x)(y)=xy pieces in total.
Therefore, a (n+5q) by (no. of pieces along length) puzzle has a total number of (2m+6p)(4n+20q) pieces.
Putting this information into equation form, we get:
(n+5q)(no. of pieces along length)=(2m+6p)(4n+20q).
By Factorising fully the term on the right side, we get:
(n+5q)(no. of pieces along length)=8(m+3p)(n+5q).
Hence, no. of pieces along length=8(m+3p)(n+5q)/(n+5q)=8(m+3p)
Hope this helps!!! You can ask me questions personally on telegram, just add my me @yuanqiiin. I will be happy to help you!
Date Posted:
2 years ago
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