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secondary 4 | A Maths
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Anyone can contribute an answer, even non-tutors.
Would appreciate a detailed explanation, as well as how to get the max and min points of the graph
Date Posted: 2 years ago
Views: 233
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2sinx has a period of 2pi and an amplitude of 2. So it reaches maximum, 2, when x = pi/2, and reaches minimum, - 2, when x = 3pi/2. And 2sinx = 0 when x = 0, pi and 2 pi.
For the line, only need 2 points to draw, so when x =0, y = 1, and when x = 2pi, y = - 1/2. And just plot these 2 points.
For the last equation given, it can be manipulated to 2sinx on one side, and 1- 3x/4pi on the other. And notice they are equal at the points of intersection (as seen on the graph i just drew). Since there are 3 intersection points, there are 3 solutions.
For the line, only need 2 points to draw, so when x =0, y = 1, and when x = 2pi, y = - 1/2. And just plot these 2 points.
For the last equation given, it can be manipulated to 2sinx on one side, and 1- 3x/4pi on the other. And notice they are equal at the points of intersection (as seen on the graph i just drew). Since there are 3 intersection points, there are 3 solutions.
Date Posted:
2 years ago
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