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primary 5 | Maths
| Fractions
2 Answers Below
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Please solve the problem
Date Posted: 2 years ago
Views: 473
fig. n →
white squares # → 4×(n-1)²
side # → 2n-1
black squares # → 1+4×(n-1)
(a) n = 5
black + white
(2n-1)² = 81 (Ans)
(b) n = 6
white
4×(n-1)²
= 4×(6-1)²
= 100 (Ans)
(c) n = 15
black
1 + 4×(15-1)
= 57 (Ans)
white squares # → 4×(n-1)²
side # → 2n-1
black squares # → 1+4×(n-1)
(a) n = 5
black + white
(2n-1)² = 81 (Ans)
(b) n = 6
white
4×(n-1)²
= 4×(6-1)²
= 100 (Ans)
(c) n = 15
black
1 + 4×(15-1)
= 57 (Ans)
See 2 Answers
done
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Well my method maybe time consuming, but it is a fool-proof way to solve it.
Black squares should be pretty easy.
White squares are the sum of all the odd numbers (For example, for Figure 6, then we add all 5 odd numbers then multiply by 4). For Figure 15, we add all 14 odd numbers then multiply by 4.
Black squares should be pretty easy.
White squares are the sum of all the odd numbers (For example, for Figure 6, then we add all 5 odd numbers then multiply by 4). For Figure 15, we add all 14 odd numbers then multiply by 4.
Date Posted:
2 years ago
Thanks a lot
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