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Secondary 1 | Maths
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Hi, can anyone please help with Q4?
Thanks in advance!
Date Posted: 3 years ago
Views: 167
Is the answer 14?
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Area of a parallelogram is base x height.
In this diagram you can see it as PQ x ST
or SU x QR.
Don’t have to use Pythagoras theorem:)
In this diagram you can see it as PQ x ST
or SU x QR.
Don’t have to use Pythagoras theorem:)
SU x QR is 112cm^2 which is area of the parallelogram.
Take QR divide by 8, you will get the answer:)
Take QR divide by 8, you will get the answer:)
done
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Date Posted:
3 years ago
Hello Anna, thank you for your workings!
Just wondering, is there another way to work on this, as Pythagoras' Theorem is not covered in Sec 1 syllabus? :)
Just wondering, is there another way to work on this, as Pythagoras' Theorem is not covered in Sec 1 syllabus? :)
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