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Question
primary 6 | Maths
| Fractions
2 Answers Below
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Please help
Date Posted: 3 years ago
Views: 587
Thanks so much I understand now ...u also write wrongly its 24 not 23 adults....thanks alot
Oh yeah my bad. Was about to comment. Glad you saw it too. It's unfortunate that once you post, can't edit it back.
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Thanks strike
Welcome
We know that,
23 Adults = 32 Children
1 Adult = 32÷23 Children
9 Adults = (32÷23) x 9
= 12 Childrens
Which means to say that the mass of 9 adults is actually the the mass of 12 children. Thus, we can take it that there are already 12 children on the boat. Since the maximum tolerated number of children is 32. There can still be 32 - 12 = 23 childrens taking the boat before the maximum is reached.
23 Adults = 32 Children
1 Adult = 32÷23 Children
9 Adults = (32÷23) x 9
= 12 Childrens
Which means to say that the mass of 9 adults is actually the the mass of 12 children. Thus, we can take it that there are already 12 children on the boat. Since the maximum tolerated number of children is 32. There can still be 32 - 12 = 23 childrens taking the boat before the maximum is reached.
I made a mistake. Sorry 32 - 12 = 20. So the answer is (2).
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