i)
x/3 + y/2 = 1
Multiply both sides by 2,
2x/3 + y = 2
y = -2x/3 + 2
y = -⅔x + 2
This is the equation of the line.

ii)
General equation of a straight line is y = mx + c, whereby :
m is the gradient
c is the y-intercept (the y-coordinate of the intersection point of the line and the y-axis. Any point on the y-axis has coordinate = 0)

So, looking at the result in i), the gradient is -⅔.

iii)
Anywhere on the x-axis, y = 0.
So substitute y = 0 into the line's equation.

0 = -⅔x + 2
⅔x = 2
x = 2/(⅔)
x = 2 × 3/2
x = 3

The coordinates of the intersection point are (3,0)