Jade's answer to sally's Secondary 3 A Maths Singapore question.
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Since line L is perpendicular to line AB, you can find the gradient of line L by dividing -1 to the gradient of line AB. ( -1 ÷ 2/3)
*refer to gradient of normal line
Since line L is the perpendicular bisector of line AB, this means that point P is the midpoint of coordinates A and B. Hence, you can find the coordinates of P.
Afterwards, you can construct your equation for line L using the formula y1 - y2 = m ( x1 - x2 )
Since point C is directly above A, the x-coordinates for both C and A are the same ( -1 )
*refer to gradient of normal line
Since line L is the perpendicular bisector of line AB, this means that point P is the midpoint of coordinates A and B. Hence, you can find the coordinates of P.
Afterwards, you can construct your equation for line L using the formula y1 - y2 = m ( x1 - x2 )
Since point C is directly above A, the x-coordinates for both C and A are the same ( -1 )
Date Posted:
3 years ago
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