J's answer to Intan's Malaysia question.
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a)
Common difference = 9 - 4 = 5
Common difference = 14 - 9 = 5
b)
Last term is 109
Difference between first and last term
= 109 - 4 = 105
Number of common differences between them = 105 ÷ 5 = 21
This means that you need to +5 for 21 times to reach the last term.
So the last term must be the 22nd term since 1 + 21 = 22
Total number of terms = 22
Common difference = 9 - 4 = 5
Common difference = 14 - 9 = 5
b)
Last term is 109
Difference between first and last term
= 109 - 4 = 105
Number of common differences between them = 105 ÷ 5 = 21
This means that you need to +5 for 21 times to reach the last term.
So the last term must be the 22nd term since 1 + 21 = 22
Total number of terms = 22
Date Posted:
3 years ago
Alternatively,
Use the A.P formula Tn = a + (n - 1)d, whereby:
d is the common difference
n is the term of terms in the progression
a is the first term.
109 = 4 + (n - 1)(5)
109 = 4 + 5n - 5
110 = 5n
n = 22
Use the A.P formula Tn = a + (n - 1)d, whereby:
d is the common difference
n is the term of terms in the progression
a is the first term.
109 = 4 + (n - 1)(5)
109 = 4 + 5n - 5
110 = 5n
n = 22
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