Eric Nicholas K's answer to Candice lim's Secondary 4 E Maths Singapore question.
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Good morning Candice! For part b we need to find some relevant lengths and cosine rule to solve the question. As it turns out, the included angle happens to be 90 degrees so the “-2ab cos C” term for the cosine rule becomes 0, reducing the formula to the Pythagoras’ Theorem.
For part c, we can simply say that because BD is parallel to AE and the length of BD is (sqrt 2) / 2 times the length of AE, the vector for BD is also (sqrt 2) / 2 times of the vector for AE.
For part c, we can simply say that because BD is parallel to AE and the length of BD is (sqrt 2) / 2 times the length of AE, the vector for BD is also (sqrt 2) / 2 times of the vector for AE.
Date Posted:
4 years ago
Candice, sqrt 2 divided by 2 is equivalent to 1 divided by sqrt 2. This is because 2 can be expressed as sqrt 2 times sqrt 2, such that sqrt 2 divided by (sqrt 2 times sqrt 2) becomes 1 divided by sqrt 2.
Good morning Mr Eric! Noted your advice with many thanks:)
And thank you so much for your time and effort in providing me with the full solution for the whole question. I really really appreciate what you have done for me thus far and I have to say without your help and advice, I probably wouldn't have come this far. Your commitment and expertise have motivated me to work harder for Mathematics which used to be not my best subjects in school.
You are the BEST teacher that I have ever come across :D
Once again thank you very much and I hope you have a great day ahead, pls take care.
And thank you so much for your time and effort in providing me with the full solution for the whole question. I really really appreciate what you have done for me thus far and I have to say without your help and advice, I probably wouldn't have come this far. Your commitment and expertise have motivated me to work harder for Mathematics which used to be not my best subjects in school.
You are the BEST teacher that I have ever come across :D
Once again thank you very much and I hope you have a great day ahead, pls take care.
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