J's answer to Shei Ling's Secondary 3 A Maths Singapore question.
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sin² x / (1 - sin² x)
= sin² x / cos² x (recall sin² x + cos² x = 1)
= (sin x / cos x)²
= (tan x)² (recall tan x = sin x / cos x
= tan² x
= sec² x - 1 (recall 1 + tan² x = sec² x)
(Proved)
= sin² x / cos² x (recall sin² x + cos² x = 1)
= (sin x / cos x)²
= (tan x)² (recall tan x = sin x / cos x
= tan² x
= sec² x - 1 (recall 1 + tan² x = sec² x)
(Proved)
Date Posted:
3 years ago
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