@mistahjfitness's answer to Ang Tiong Boon's Primary 6 Maths Data Analysis Singapore question.
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BCD total = 94 x 3 = 282
Bob = 96.
Assuming D= 91 (higher than 90)
Highest possible score for C= 282-96-91=95
Bob = 96.
Assuming D= 91 (higher than 90)
Highest possible score for C= 282-96-91=95
Date Posted:
3 years ago
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