Kahwai's answer to ✨'s Secondary 2 Maths Singapore question.
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(6 x 7 + 7 x 10 + 6 x 10)/2
Plus
a= (6^2 + 7^2)^0.5
b= (6^ 2 + 10^2)^0.5
c= (10^2+7^2)^0.5
s = 1/2(a+b+c)
Area of the forth triangle = [(s-a) (s-b) (s-c)]^0.5
Plus
a= (6^2 + 7^2)^0.5
b= (6^ 2 + 10^2)^0.5
c= (10^2+7^2)^0.5
s = 1/2(a+b+c)
Area of the forth triangle = [(s-a) (s-b) (s-c)]^0.5
Date Posted:
3 years ago
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