Potatoo's answer to Jung Wook Young's Secondary 2 Maths Singapore question.
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5d) 3 ohm
5e) 1A
5f) 1A [For series circuit , the amount of current is the same through any component.]
5g) 1A
6ai) 0.5A
6aii) 0.5A
6aiii) 0.5A
6biv) 1V
6bv) 2.5V
6bvi) 5V-2.5V-1V= 1.5V
[The supply voltage in a series circuit is equal to the sum of the individual voltage drops.]
5e) 1A
5f) 1A [For series circuit , the amount of current is the same through any component.]
5g) 1A
6ai) 0.5A
6aii) 0.5A
6aiii) 0.5A
6biv) 1V
6bv) 2.5V
6bvi) 5V-2.5V-1V= 1.5V
[The supply voltage in a series circuit is equal to the sum of the individual voltage drops.]
Date Posted:
3 years ago
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