Yee Miao Ling's answer to claire chen's Secondary 4 A Maths question.

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Yee Miao Ling
Yee Miao Ling's answer
29 answers (Tutor Details)
Hi, just to offer an alternative solution, by using Remainder Theorem. This is a shorter method. The catch is you need to use remainder theorem to save time instead of doing long division.
But if you're unfamiliar with remainder theorem or find yourself weak in the area, then the solution above may be more suited for you. :)