Eric Nicholas K's answer to LockB's Secondary 3 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Q10
The rest I look another time
The rest I look another time
Date Posted:
3 years ago
i still dont really understand part ii tho
btw for questions like part iii, if the constant term does not contain x, we have to see which term in the expansion combined together will give a term that does not contain x, if it contain x or x^2 we have to see which term combines to give a term with x and x^2?
btw for questions like part iii, if the constant term does not contain x, we have to see which term in the expansion combined together will give a term that does not contain x, if it contain x or x^2 we have to see which term combines to give a term with x and x^2?
For part ii, you need to realise that 0.999^8 is the same as (1 - 0.001)^8, since 1 - 0.001 = 0.999. This is because we are asked to use the results from the first part, and we must look at how part ii is related to part i. Here, the exponents are the same at 8, so to use part i result, we have to rewrite 0.999 as 1 - 0.001, or in this case, 1 - 0.003/3.
-------------------------------------
"if it contain x or x^2 we have to see which term combines to give a term with x and x^2?"
Yes, you will have to compare the corresponding expressions.
-------------------------------------
"if it contain x or x^2 we have to see which term combines to give a term with x and x^2?"
Yes, you will have to compare the corresponding expressions.