Cari's answer to Jane Grey's Secondary 3 E Maths Singapore question.
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Angle DCA =Angle DBA = 58
Angle DAB = 180 - 54 - 58 = 68
Angle ACB = Angle ADB = 54
Angle CAB = 180-100-54= 26
Angle CDB = Angle CAB = 26
Angle APD = 180 - 26 - 54 - 68 = 32
Angle DAB = 180 - 54 - 58 = 68
Angle ACB = Angle ADB = 54
Angle CAB = 180-100-54= 26
Angle CDB = Angle CAB = 26
Angle APD = 180 - 26 - 54 - 68 = 32
Date Posted:
4 years ago
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