TutorAnywhr Home Tuition Agency's answer to Janice lim's Primary 6 Maths Fractions Singapore question.
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Let x cm/s be the speed of Neptune.
Speed of Jupiter = (x+20) cm/s
Distance covered in 12 seconds:
Neptune: 12x cm (2/3 of the race, so entire race distance would be 18x cm)
Jupiter: (x+20) * 12 = 12x+240 cm (entire race distance)
Hence, 12x + 240 = 18x
Solve x = 40.
Total distance of race (solve using either Neptune or Jupiter):
12 (40) + 240 = 720cm
Or
18 (40) = 720cm
Let x cm/s be the speed of Neptune.
Speed of Jupiter = (x+20) cm/s
Distance covered in 12 seconds:
Neptune: 12x cm (2/3 of the race, so entire race distance would be 18x cm)
Jupiter: (x+20) * 12 = 12x+240 cm (entire race distance)
Hence, 12x + 240 = 18x
Solve x = 40.
Total distance of race (solve using either Neptune or Jupiter):
12 (40) + 240 = 720cm
Or
18 (40) = 720cm
Date Posted:
4 years ago
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