J's answer to Koh Yun Xiang's Secondary 1 Maths Singapore question.
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V = 3^9 x 7^6 x 11³
= (3³)³ x (7²)³ x 11³
= (3³ x 7² x 11)³
So ³√V
= ³√(3³ x 7² x 11)³
= 3³ x 7² x 11
= 27 x 49 x 11
= 14553
= (3³)³ x (7²)³ x 11³
= (3³ x 7² x 11)³
So ³√V
= ³√(3³ x 7² x 11)³
= 3³ x 7² x 11
= 27 x 49 x 11
= 14553
Date Posted:
3 years ago
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