Eric Nicholas K's answer to Vignesh anand's Secondary 3 A Maths Singapore question.
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I could not decide on whether k = -2 exists or not. The case k = -2 leads to multiple, infinite solutions possible, so the intersection is "everywhere" rather than "a single point P".
If I were to use this definition, then I would reject k = -2 even in the fourth part, because I need "P" to be a single defined point.
If I were to use this definition, then I would reject k = -2 even in the fourth part, because I need "P" to be a single defined point.
Date Posted:
3 years ago
Thanks a lot