Christmas MT's answer to Tan's Junior College 1 H2 Maths question.
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First find amount of NaOH, and from there you know the amount of OH- ions.
OH- and H+ react in a 1-to-1 ratio to form water, so amount of H+ ions = amount of OH- ions.
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They gave [CH3COOH], so from there we can find the amount of CH3COOH, and the amount of H+ ions contributed by it in the reaction.
The remaining H+ ions must come from (COOH)2.
Remember that 1 (COOH)2 = 2H+, therefore amount of (COOH)2 needs to be halved.
Lastly, find [(COOH)2].
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Feels like doing a problem sum isn't it?
OH- and H+ react in a 1-to-1 ratio to form water, so amount of H+ ions = amount of OH- ions.
---
They gave [CH3COOH], so from there we can find the amount of CH3COOH, and the amount of H+ ions contributed by it in the reaction.
The remaining H+ ions must come from (COOH)2.
Remember that 1 (COOH)2 = 2H+, therefore amount of (COOH)2 needs to be halved.
Lastly, find [(COOH)2].
---
Feels like doing a problem sum isn't it?
Date Posted:
7 years ago
Bleh, 3 minutes too slow.
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