Tan Yick Loong's answer to Sadique's Primary 6 Maths Percentage Singapore question.
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Assume Bala has 10 parts.
A has 10% more than Bala. So A has 10*110% = 11 parts
C has 30% less than Bala. So C has 10*(100%-30%) = 10*70% = 7 parts.
Total parts = 11+10+7 = 28
28 parts = $840
1 part = $840/28 = $30
Therefore, Bala, who has 10 parts, has: 10* $30 = $300
A has 10% more than Bala. So A has 10*110% = 11 parts
C has 30% less than Bala. So C has 10*(100%-30%) = 10*70% = 7 parts.
Total parts = 11+10+7 = 28
28 parts = $840
1 part = $840/28 = $30
Therefore, Bala, who has 10 parts, has: 10* $30 = $300
Date Posted:
4 years ago
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