Eric Nicholas K's answer to Candice lim's Secondary 3 A Maths Singapore question.
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A very good evening to you Candice!!! Here are my workings for this question.
Date Posted:
4 years ago
Candice, remember that it’s vertical against horizontal.
“When a graph of y against x...” means y is the vertical and x is the horizontal.
“When a graph of x against y...” means x is the vertical and y is the horizontal.
Oh yes, I left out part ii.
y = 3x^2 divided by (x - 4)
When y = 48,
48 = 3x^2 divided by (x - 4)
48 (x - 4) = 3x^2
16 (x - 4) = x^2
16x - 64 = x^2
0 = x^2 - 16x + 64
0 = (x - 8) (x - 8)
x = 8
“When a graph of y against x...” means y is the vertical and x is the horizontal.
“When a graph of x against y...” means x is the vertical and y is the horizontal.
Oh yes, I left out part ii.
y = 3x^2 divided by (x - 4)
When y = 48,
48 = 3x^2 divided by (x - 4)
48 (x - 4) = 3x^2
16 (x - 4) = x^2
16x - 64 = x^2
0 = x^2 - 16x + 64
0 = (x - 8) (x - 8)
x = 8
Thank you so much, Mr Eric. I know where is my mistake now. Thanks and have a good evening too. Take care :)
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